Write a polynomial function of least degree with integral coefficients that has the given zeros. –2, –3,3 – 6i

Answer:f(x) = (x+2)(x+3)(x-(3-6i))(x-(3+6i))f(x) = 270 + 189 x + 21 x^2 - x^3 + x^4Step-by-step explanation:First of all, we must know that complex roots come in conjugate pairs.So the zeros of your equation would bex = -2x = -3x = 3 - 6ix = 3 + 6iYour polynomial is of fourth degree.f(x) = (x-(-2))(x-(-3))(x-(3-6i))(x-(3+6i))f(x) = (x+2)(x+3)(x-(3-6i))(x-(3+6i))Please , see attached image below for full expressionf(x) = 270 + 189 x + 21 x^2 - x^3 + x^4