Q:

2. Given the coordinates, classify triangle QRT by its sides. Q(-2, -1), R(1,5), T(-8,-4)Classify:​

Accepted Solution

A:
Answer:The measure of sides of triangle with given points areQR = 3[tex]\sqrt{5}[/tex]  unitRT = 9[tex]\sqrt{2}[/tex]  unitTQ =  [tex]\sqrt{13}[/tex]  unit Step-by-step explanation:Given as :The coordinate of Triangle QRT as :Q = ( - 2 , - 1 )R = ( 1 , 5 )T = ( - 8 , - 4 )Now , The Distance between the points can be measure as :QR = [tex]\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}[/tex]Or, QR =  [tex]\sqrt{(1+2)^{2}+(5+1)^{2}}[/tex]Or, QR = [tex]\sqrt{(3)^{2}+(6)^{2}}[/tex] Or, QR = [tex]\sqrt{45}[/tex] = 3[tex]\sqrt{5}[/tex]  unitSimilarlyRT =  [tex]\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}[/tex]Or, RT =  [tex]\sqrt{(-8-1)^{2}+(-4-5)^{2}}[/tex]Or,  RT =  [tex]\sqrt{(-9)^{2}+(-9)^{2}}[/tex]Or, RT =  [tex]\sqrt{162}[/tex] = 9[tex]\sqrt{2}[/tex]  unitAndTQ =  [tex]\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}[/tex]Or, TQ =  [tex]\sqrt{(-2+8)^{2}+(-1+4)^{2}}[/tex]Or, TQ = [tex]\sqrt{(2)^{2}+(3)^{2}}[/tex] Or, TQ = [tex]\sqrt{13}[/tex]  unitHence The measure of sides of triangle with given points areQR = 3[tex]\sqrt{5}[/tex]  unitRT = 9[tex]\sqrt{2}[/tex]  unitTQ =  [tex]\sqrt{13}[/tex]  unit         Answer